Day-14-Angle Between Hands of a Clock.cpp

Given two numbers, hour and minutes. Return the smaller angle (in degrees) formed between the hour and the minute hand.



Example 1:



Input: hour = 12, minutes = 30
Output: 165
Example 2:



Input: hour = 3, minutes = 30
Output: 75
Example 3:



Input: hour = 3, minutes = 15
Output: 7.5
Example 4:

Input: hour = 4, minutes = 50
Output: 155
Example 5:

Input: hour = 12, minutes = 0
Output: 0


Constraints:

1 <= hour <= 12
0 <= minutes <= 59
Answers within 10^-5 of the actual value will be accepted as correct.
   Hide Hint #1
The tricky part is determining how the minute hand affects the position of the hour hand.
   Hide Hint #2
Calculate the angles separately then find the difference.








class Solution {
public:
    double angleClock(int hour, int minutes) {
        double dh = 30*hour + 0.5*minutes;
        double dm = 0*hour + 6*minutes;

        double angle = abs(dh-dm);

        if(angle>180) angle=360-angle;

        return angle;
    }
};

//  degree made by hour hand in 1 hour   360/12=30
// degree made by hour hand in 1 minute   30/60=0.5
// degree made by minute hand in 1 hour    0 as it comes back to its initial position
// degree made by minute hand in 1 minute  360/60=6